Find names of employees with even-length names?

Short answer: Find names of employees with even-length names var evenNames = employees .Where(e => e.Name.Length % 2 == 0) .Select(e => e.Name); Find names of employees with even-length names var evenNames = employees .Where(e => e.Name.Length % 2 == 0) .Select(e => e.Name); Find names of employees with even-length names var evenNames = employees .Where(e =>… e.Name.Length % 2 == 0) .Select(e => e.Name); Find names of employees…

Explain a bit more

with even-length names var evenNames = employees .Where(e => e.Name.Length % 2 == 0) .Select(e => e.Name);

Real-world example (ShopNest)

ShopNest uses LINQ to query orders: filter by date, project to a summary DTO, and order by total—readable C# that becomes SQL under EF Core.

Say this in the interview

1. Define — one clear sentence (the short answer above).
2. Example — relate it to a project like ShopNest or your real work.
3. Trade-off — when you would not use it.