Find the single non-repeated element in an array where every other?

element appears twice

public int SingleNonRepeated(int[] nums) {
int result = 0;
foreach (int num in nums) {
result ^= num;
}
return result;
}

Explanation:

XOR of a number with itself is 0; XOR with 0 is the number. So duplicates cancel out,

leaving the unique number.

Follow on: