Nutanix Medium csharp

Koko Eating Bananas

Animated walkthrough

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Nutanix interview context: Koko Eating Bananas is a Medium Binary Search problem — Binary search on index or on the answer (binary search on value).

Use the animation above to step through each move before writing code.

Pattern: Binary Search

Read from stdin, write to stdout. Classic interview problem #875.

Problem

Koko Eating Bananas — Nutanix interview prep · Binary Search

Classic interview problem #875.

Input (stdin)

Line 1: n piles\nLine 2: pile sizes\nLine 3: hours h

Output (stdout)

Minimum eating speed k

Your program must read from stdin and write the answer to stdout (no extra debug text).

Examples

Sample
Input
4
3 6 7 11
8
Output
4
Hints
  • Input format: Line 1: n piles\nLine 2: pile sizes\nLine 3: hours h
  • DSA Interview 150 — Binary Search
  • Problem #875
  • Frequently asked at Nutanix
  • Binary Search

Your solution

TestStatusDetails
Ready — edit the code above and click Run or Submit.

Solution

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

class Program
{
    static int[] Ria(string line = null)
    {
        line ??= Console.ReadLine();
        if (string.IsNullOrWhiteSpace(line)) return Array.Empty<int>();
        return line.Trim().Split(new[] { ' ', ',', '\t' }, StringSplitOptions.RemoveEmptyEntries)
            .Select(int.Parse).ToArray();
    }
    static string[] Rsa()
    {
        int n = int.Parse(Console.ReadLine());
        var arr = new string[n];
        for (int i = 0; i < n; i++) arr[i] = Console.ReadLine();
        return arr;
    }
    static void W(params object[] parts) => Console.WriteLine(string.Join(" ", parts));
    static void Wb(bool v) => Console.WriteLine(v ? "true" : "false");
    static void Wi(int v) => Console.WriteLine(v);
    static void Ws(string v) => Console.WriteLine(v);

    static void Main()
    {
int n = int.Parse(Console.ReadLine());
var piles = Ria();
int h = int.Parse(Console.ReadLine());
bool Can(int speed) {
    long hours = 0;
    foreach (var p in piles) hours += (p + speed - 1) / speed;
    return hours <= h;
}
int lo = 1, hi = piles.Max(), ans = hi;
while (lo <= hi) {
    int mid = lo + (hi - lo) / 2;
    if (Can(mid)) { ans = mid; hi = mid - 1; } else lo = mid + 1;
}
Wi(ans);
    }
}

Try solving on your own first, then reveal the official answer.

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