Morgan Stanley Medium csharp

Reverse Integer

Animated walkthrough

Step through the algorithm visually — use Play or the step buttons (inspired by AlgoMaster / visualgo).

Step 1 / 1

Morgan Stanley interview context: Reverse Integer is a Medium Bit Manipulation problem — XOR tricks, masks, and bit counts — frequent in Google/Meta screens.

Use the animation above to step through each move before writing code.

Pattern: Bit Manipulation

Read from stdin, write to stdout. Classic interview problem #7.

Problem

Reverse Integer — Morgan Stanley interview prep · Bit Manipulation

Classic interview problem #7.

Input (stdin)

Line 1: integer x

Output (stdout)

Reversed int (0 on overflow)

Your program must read from stdin and write the answer to stdout (no extra debug text).

Examples

Sample
Input
123
Output
321
Hints
  • Input format: Line 1: integer x
  • DSA Interview 150 — Bit Manipulation
  • Problem #7
  • Frequently asked at Morgan Stanley
  • Bit Manipulation

Your solution

TestStatusDetails
Ready — edit the code above and click Run or Submit.

Solution

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

class Program
{
    static int[] Ria(string line = null)
    {
        line ??= Console.ReadLine();
        if (string.IsNullOrWhiteSpace(line)) return Array.Empty<int>();
        return line.Trim().Split(new[] { ' ', ',', '\t' }, StringSplitOptions.RemoveEmptyEntries)
            .Select(int.Parse).ToArray();
    }
    static string[] Rsa()
    {
        int n = int.Parse(Console.ReadLine());
        var arr = new string[n];
        for (int i = 0; i < n; i++) arr[i] = Console.ReadLine();
        return arr;
    }
    static void W(params object[] parts) => Console.WriteLine(string.Join(" ", parts));
    static void Wb(bool v) => Console.WriteLine(v ? "true" : "false");
    static void Wi(int v) => Console.WriteLine(v);
    static void Ws(string v) => Console.WriteLine(v);

    static void Main()
    {
int x = int.Parse(Console.ReadLine());
long rev = 0, n = x;
while (n != 0) {
    rev = rev * 10 + n % 10;
    n /= 10;
    if (rev > int.MaxValue || rev < int.MinValue) { rev = 0; break; }
}
Wi((int)rev);
    }
}

Try solving on your own first, then reveal the official answer.

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