Step through the algorithm visually — use Play or the step buttons (inspired by AlgoMaster / visualgo).
LinkedIn interview context: Course Schedule is a Medium Graphs problem — BFS for shortest path in unweighted graphs; DFS for connectivity and cycles.
Use the animation above to step through each move before writing code.
Pattern: Graphs
Read from stdin, write to stdout. Classic interview problem #207.
Course Schedule — LinkedIn interview prep · Graphs
Classic interview problem #207.
Input (stdin)
Line 1: numCourses\nLine 2: numEdges\nNext: a b edges
Output (stdout)
true if can finish all courses
Your program must read from stdin and write the answer to stdout (no extra debug text).
2 1 1 0
true
| Test | Status | Details |
|---|
Ready — edit the code above and click Run or Submit.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
class Program
{
static int[] Ria(string line = null)
{
line ??= Console.ReadLine();
if (string.IsNullOrWhiteSpace(line)) return Array.Empty<int>();
return line.Trim().Split(new[] { ' ', ',', '\t' }, StringSplitOptions.RemoveEmptyEntries)
.Select(int.Parse).ToArray();
}
static string[] Rsa()
{
int n = int.Parse(Console.ReadLine());
var arr = new string[n];
for (int i = 0; i < n; i++) arr[i] = Console.ReadLine();
return arr;
}
static void W(params object[] parts) => Console.WriteLine(string.Join(" ", parts));
static void Wb(bool v) => Console.WriteLine(v ? "true" : "false");
static void Wi(int v) => Console.WriteLine(v);
static void Ws(string v) => Console.WriteLine(v);
static void Main()
{
int n = int.Parse(Console.ReadLine());
int m = int.Parse(Console.ReadLine());
var adj = new List<int>[n];
for (int i = 0; i < n; i++) adj[i] = new List<int>();
for (int i = 0; i < m; i++) {
var e = Ria();
adj[e[1]].Add(e[0]);
}
var indeg = new int[n];
foreach (var list in adj) foreach (var v in list) indeg[v]++;
var q = new Queue<int>();
for (int i = 0; i < n; i++) if (indeg[i] == 0) q.Enqueue(i);
int seen = 0;
while (q.Count > 0) {
int u = q.Dequeue(); seen++;
foreach (var v in adj[u]) if (--indeg[v] == 0) q.Enqueue(v);
}
Wb(seen == n);
}
}
Try solving on your own first, then reveal the official answer.