Atlassian Medium csharp

Generate Parentheses

Animated walkthrough

Step through the algorithm visually — use Play or the step buttons (inspired by AlgoMaster / visualgo).

Step 1 / 1

Atlassian interview context: Generate Parentheses is a Medium Stack problem — Monotonic stack or bracket matching — watch for O(n) single-pass solutions.

Use the animation above to step through each move before writing code.

Pattern: Stack

Read from stdin, write to stdout. Classic interview problem #22.

Problem

Generate Parentheses — Atlassian interview prep · Stack

Classic interview problem #22.

Input (stdin)

Line 1: n pairs

Output (stdout)

Count of valid combinations (n=3 → 5)

Your program must read from stdin and write the answer to stdout (no extra debug text).

Examples

Sample
Input
3
Output
5
Hints
  • Input format: Line 1: n pairs
  • DSA Interview 150 — Stack
  • Problem #22
  • Frequently asked at Atlassian
  • Stack

Your solution

TestStatusDetails
Ready — edit the code above and click Run or Submit.

Solution

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

class Program
{
    static int[] Ria(string line = null)
    {
        line ??= Console.ReadLine();
        if (string.IsNullOrWhiteSpace(line)) return Array.Empty<int>();
        return line.Trim().Split(new[] { ' ', ',', '\t' }, StringSplitOptions.RemoveEmptyEntries)
            .Select(int.Parse).ToArray();
    }
    static string[] Rsa()
    {
        int n = int.Parse(Console.ReadLine());
        var arr = new string[n];
        for (int i = 0; i < n; i++) arr[i] = Console.ReadLine();
        return arr;
    }
    static void W(params object[] parts) => Console.WriteLine(string.Join(" ", parts));
    static void Wb(bool v) => Console.WriteLine(v ? "true" : "false");
    static void Wi(int v) => Console.WriteLine(v);
    static void Ws(string v) => Console.WriteLine(v);

    static void Main()
    {
int n = int.Parse(Console.ReadLine());
var res = new List<string>();
void Dfs(int open, int close, StringBuilder sb) {
    if (sb.Length == 2 * n) { res.Add(sb.ToString()); return; }
    if (open < n) { sb.Append('('); Dfs(open + 1, close, sb); sb.Length--; }
    if (close < open) { sb.Append(')'); Dfs(open, close + 1, sb); sb.Length--; }
}
Dfs(0, 0, new StringBuilder());
Wi(res.Count);
    }
}

Try solving on your own first, then reveal the official answer.

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